Question #13b41

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Answer 1 · 2016-03-05T06:32:12

$f (g (2)) = - 4$ $f(g(2)) = -4$
$g (f (x)) = \sqrt{3 x - 6}$ $g(f(x)) = sqrt(3x - 6)$

$f (x) = 3 x - 4$ $f(x) = 3x - 4$

$g (x) = \sqrt{x - 2}$ $g(x) = sqrt(x - 2)$

$f (g (x)) = 3 \cdot g (x) - 4$ $f(g(x)) = 3*g(x) - 4$

$\Rightarrow f (g (x)) = 3 (\sqrt{x - 2}) - 4$ $=> f(g(x)) = 3(sqrt(x - 2)) - 4$

$\Rightarrow f (g (2)) = 3 (\sqrt{2 - 2}) - 4$ $=> f(g(2)) = 3(sqrt(2 - 2)) - 4$

$\Rightarrow f (g (2)) = 3 \sqrt{0} - 4$ $=> f(g(2)) = 3sqrt0 - 4$

$\Rightarrow f (g (2)) = - 4$ $=> f(g(2)) = -4$

$g (f (x)) = \sqrt{f (x) - 2}$ $g(f(x)) = sqrt(f(x) - 2)$

$\Rightarrow g (f (x)) = \sqrt{(3 x - 4) - 2}$ $=> g(f(x)) = sqrt((3x - 4) - 2)$

$\Rightarrow g (f (x)) = \sqrt{3 x - 6}$ $=> g(f(x)) = sqrt(3x - 6)$