Question #91a8b

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Answer 1 · 2016-03-05T06:43:18

$log 20 = 1.301$ $log 20 = 1.301$
$log 2.5 = 0.398$ $log 2.5 = 0.398$
$log 125 = 2.097$ $log 125 = 2.097$

$log a b = log a + log b$ $log ab = log a + log b$

$\frac{log a}{b} = log a - log b$ $log a/b = log a - log b$

${log a}^{b} = b \cdot log a$ $log a^b = b * log a$

$log 20 = log 4 \cdot 5 = log 2 \cdot 2 \cdot 5$ $log 20 = log 4*5 = log 2*2*5$

$\Rightarrow log 20 = log 2 + log 2 + log 5$ $=> log 20 = log 2 + log 2 + log 5$

$\Rightarrow log 20 = 0.301 + 0.301 + 0.699$ $=> log 20 = 0.301 + 0.301 + 0.699$

$\Rightarrow log 20 = 1.301$ $=> log 20 = 1.301$

$log 2.5 = log (\frac{5}{2})$ $log 2.5 = log (5/2)$

$\Rightarrow log 2.5 = log 5 - log 2$ $=> log 2.5 = log 5 - log 2$

$\Rightarrow log 2.5 = 0.699 - 0.301$ $=> log 2.5 = 0.699 - 0.301$

$\Rightarrow log 2.5 = 0.398$ $=> log 2.5 = 0.398$

$log 125 = {log 5}^{3} = 3 \cdot log 5$ $log 125 = log 5^3 = 3 * log 5$

$\Rightarrow log 125 = 3 \cdot 0.699$ $=> log 125 = 3 * 0.699$

$\Rightarrow log 125 = 2.097$ $=> log 125 = 2.097$