How do we solve 6^3t-1=5 for $t$ ?

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Answer 1 · 2016-06-05T07:09:24

$t=1/3log_6(30)$

In the absence of proper formatting I believe it is

$6^(3t-1)=5$ . If so

$log_(6)5=3t-1$ or

$3t=log_(6)5+1=log_(6)5+log_(6)6=log_(6)(5xx6)$

$3t=log_6(30)$

Hence, $t=1/3log_6(30)$

Answer 2 · 2016-06-05T08:38:56

For $6^(3t)-1=5$ , the answer is $t = 1/3$ .
For $6^(3t-1)=5$ , the answer is $t=(1+log 5/log 6)/3$ .

If it is $6^(3t)-1=5$ then $6^(3t)=6$ .

So, $3t = 1 and t = 1/3$ .

For $6^(3t-1)=5$ , equate logarithms.

$(3t-1) log 6 = log 5$ . Solving,

$t=(1+log 5/log 6)/3$ .

How do we solve 6^3t-1=5 for tt?