Question #16930

1 Answer
Mar 9, 2016

I found 12g

Explanation:

Here you could use the expression for the heat Q exchanged as:
Q=mC_pDeltaT
that with your data gives us:
216=m*0.9*(35-15)
so that:
m=(216)/(0.9*20)=12g

I think you have for aluminium:
C_p=0.9J/(gcolor(red)(°C))