Question #5440f

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Question #5440f

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Answer 1 · 2016-03-18T11:10:23

A seconds pendulum is defined as a pendulum whose time period is exactly equal to 2 seconds.

Explanation:

Alternatively seconds pendulum has frequency equal to $\frac{1}{2} H z$ $1/2 Hz$ . It takes one second to move from one extreme to the other while swinging and takes again one second for the return swing to the other end.

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If we ignore air resistance, and for small swings we know that, time for one complete oscillation of a pendulum $T = 2 π \sqrt{\frac{L}{g}}$ $T=2 pisqrt(L/g)$
where $L and g$ $L and g$ are length of the pendulum and acceleration due to gravity respectively.
Therefore, length of Seconds pendulum $L_{\circ} = \frac{g}{π^{2}}$ $L_@=g/pi^2$ ,
inserting standard $g = 9.80665 m s^{- 2}$ $g=9.80665 ms^-2$ , We obtain its length as
$L = \frac{9.80665}{π^{2}} = 0.994 m$ $L=9.80665/pi^2=0.994m$ rounded to third place of decimal.

If someone asks you about a Seconds pendulum on moon, only answer is about its defined time period.

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Question #5440f

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