Question #4badc

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Answer 1 · 2016-04-19T06:01:12

0.8 mol

As per the equation

$H_{2}$ $H_2$ (g) + $O_{2}$ $O_2$ (g) -----> 2 $H_{2}$ $H_2$ O (l)

1 mol of $O_{2}$ $O_2$ is required to produce 2 moles of $H_{2}$ $H_2$ O

x mol of $O_{2}$ $O_2$ is required to produce 1.60 moles of $H_{2}$ $H_2$ O

setting up the ratio , we get

(1 mol of $O_{2}$ $O_2$ / X mol of $O_{2}$ $O_2$ ) = (2 mol of $H_{2}$ $H_2$ O / 1.6 mol of $H_{2}$ $H_2$ O)

1 / x = 2 /1.6

1 x 1.6 = 2.x

1.6 = 2x

x= 0.8 mol