Question #9a3ca
1 Answer
Oct 5, 2017
Very simple approach...
See the answer below...
Hope it helps...
Explanation:
We definitely know
If we get
#sinx=1/2# then we can use the formula,
i.e,
#(1/2)^2+cos^2x=1#
#=>cos^2x=3/4#
#=>cosx=sqrt3/2# Similarly,
#(1/4)^2+cos^2y=1#
#=>cos^2y=15/16#
#=>cosy=sqrt15/4#
Thank you...
