Question #92c8a

1 Answer
Oscar L.
May 17, 2016

["OH"^-]=1.8\times10^{-10}" M"[OH−]=1.8×10−10 M.

Explanation:

Use the autoionization equilibrium constant for water:

2"H"_2"O"->"H"_3"O"^++"OH"^-2H2O→H3O++OH−

"K"_w="[H"_3"O"^+]["OH"^-]=1.0\times10^{-14}" M"^2Kw=[H3O+][OH−]=1.0×10−14 M2 at 25°"C"

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