Question

If `pH=0.325` for an aqueous solution, what is `[HO^-]`?

Answer 1

`[HO^-]~=3xx10^-14*mol*L^-1`. The low `pH` specifies AN ACIDIC solution....

Explanation:

`K_w=10^-14=[H_3O^+][HO^-]` under standard conditions of `298*K` and (near to) `1*atm` pressure.........

It is usually simpler to convert this `pH` and `pOH` values than pfaff about with exponential products........

`14=pH+pOH`; `pH=-log_10(0.325)=0.488`; and `pOH=13.51`..

`[HO^-]=10^(-13.51)*mol*L^-1=??*mol*L^-1`