Question #f6f93

Question

Question #f6f93

1 Answer

Impact of this question

4014 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-18T05:39:32

Proof below

Explanation:

$8 {sin}^{2} x {cos}^{2} x = 2 \cdot 2 sin x cos x \cdot 2 sin x cos x$ $8sin^2xcos^2x=2*2sinxcosx*2sinxcosx$
First rule you'll need to know: $2 sin A cos A = sin 2 A$ $2sinAcosA=sin2A$
$= 2 \cdot sin 2 x \cdot sin 2 x$ $=2*sin2x*sin2x$
$= 2 \cdot {sin}^{2} (2 x)$ $=2*sin^2(2x)$
$= 1 - 1 + 2 \cdot {sin}^{2} (2 x)$ $=1-1+2*sin^2(2x)$
$= 1 - (1 - 2 {sin}^{2} (2 x))$ $=1-(1-2sin^2(2x))$
Second rule you'll need to know: $1 - 2 {sin}^{2} A = cos 2 A$ $1-2sin^2A=cos2A$
$= 1 - cos 4 x$ $=1-cos4x$

Science

Math

Humanities

... and beyond

Question #f6f93

1 Answer

Explanation:

Related questions

Impact of this question