Question #23690

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Answer 1 · 2016-06-09T02:58:28

Logarithmic equation $log_(1/4) 256=-4$

Exponential equation $(1/4)^(-4)=256$

Choose letter (A)

Logarithmic Equation takes the form

$log_b M=x$

Exponential Equation takes the form

$b^x=M$

The given logarithmic equation is $log_(1/4) 256=-4$

and $b=1/4$ and $M=256$ and $x=-4$

Therefore, its exponential form is

$b^x=m=M$

$(1/4)^(-4)=256$

God bless....I hope the explanation is useful.