What is the rectangular coordinate form of the polar coordinates $(r, \frac{π}{6})$ $(r, pi/6)$ ?

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What is the rectangular coordinate form of the polar coordinates $(r, \frac{π}{6})$ $(r, pi/6)$ ?

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Answer 1 · 2016-05-03T18:57:30

$(r, \frac{π}{6})$ $(r, pi/6)$ in polar form is $(\frac{\sqrt{3}}{2} r, \frac{r}{2})$ $(sqrt(3)/2 r, r/2)$ in rectangular form

Explanation:

$θ = \frac{π}{6}$ $theta = pi/6$ only gives you the angle.

You need a radius too, but $(r, \frac{π}{6})$ $(r, pi/6)$ in polar form is $(\frac{\sqrt{3}}{2} r, \frac{r}{2})$ $(sqrt(3)/2r, r/2)$ in rectangular form.

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$\frac{π}{6}$ $pi/6$ is one half of an internal angle of an equilateral triangle.

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What is the rectangular coordinate form of the polar coordinates $(r, \frac{π}{6})$ $(r, pi/6)$ ?

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What is the rectangular coordinate form of the polar coordinates $(r, \frac{π}{6})$ $(r, pi/6)$ ?