Question #e9190

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Answer 1 · 2016-04-19T06:11:37

318 atm

Let us calculate the Pressure at the standard temperature.

$P_1$ = 370 atm , $T_1$ = 323 K , n = 54 mol

$P_2$ = X atm , $T_2$ = 273 K , n = 54 mol

Using Ratios, we can get ;

$P_1$ / $T_1$ = $P_2$ / $T_2$

370 atm / 323 K = X atm / 273 K

X atm = (370 atm x 273 K \ 323 K )

X atm = 318 atm