Question #d5593

1 Answer
Oscar L.
Apr 20, 2016

6.8

Explanation:

[OH^-]=6.4\times10^{-8}
[H^+]\times[OH^-]=10^{-14}, the autoionization constant for water.

So...

[H^+]=1.6\times10^{-7}

And then:

pH=-\log_{10}[H^+]=6.8

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