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Answer 1 · 2016-10-03T17:07:57

#sf((a))#

#sf([HCl]=0.5056color(white)(x)"mol/l")#

#sf((b))#

#sf([RbOH]=0.9118color(white)(x)"mol/l")#

#sf((a))#

Start with the equation:

#sf(Ba(OH)_(2)+2HClrarrBaCl_2+2H_2O)#

#sf(c=n/v)#

#:.##sf(n=cxxv)#

#:.##sf(n_(Ba(OH)_2)=0.1529xx43.09=6.5884color(white)(x)"mmol")#

From the equation we can see that the no. moles of #sf(HCl)# must be twice this.

#:.##sf(n_(HCl)=6.5884xx2=13.177color(white)(x)"mmol")#

#:.##sf([HCl]=c/v=(13.177xxcancel(10^(-3)))/(26.06/(cancel(1000)))=0.5056color(white)(x)"mol/l")#

#sf((b))#

#sf(HCl+RbOHrarrRbCl+H_2O)#

#sf(n_(HCl)=cxxv=0.5056xx27.05=13.676color(white)(x)"mmol")#

From the equation we can see that the no. moles of #sf(RbOH)# must be the same .

#:.##sf(n_(RbOH)=13.676color(white)(x)"mmol")#

#:.##sf([RbOH]=c/v=(13.676xxcancel(10^(-3)))/(15.00/(cancel(1000)))=0.9118color(white)(x)"mol/l")#