A $2500 \cdot m^{3}$ $2500m^3$ volume of gas under $200 \cdot k P a$ $200kPa$ pressure is compressed to $500 \cdot k P a$ $500*kPa$ . What is the new volume?

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A $2500 \cdot m^{3}$ $2500m^3$ volume of gas under $200 \cdot k P a$ $200kPa$ pressure is compressed to $500 \cdot k P a$ $500*kPa$ . What is the new volume?

1 Answer

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Answer 1 · 2016-05-11T06:19:56

Given constant temperature, we use Boyle's law, $P \propto \frac{1}{V}$ $Pprop1/V$

Explanation:

So $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , and thus,

$V_{2}$ $V_2$ $=$ $=$ $\frac{P_{1} V_{1}}{P_{2}}$ $(P_1V_1)/P_2$ $=$ $=$ $\frac{200 \cdot k P a \times 2500 \cdot m^{3}}{500 \cdot k P a}$ $(200*kPaxx2500*m^3)/(500*kPa)$ $=$ $=$ $? ? \cdot m^{3}$ $??*m^3$

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A $2500 \cdot m^{3}$ $2500m^3$ volume of gas under $200 \cdot k P a$ $200kPa$ pressure is compressed to $500 \cdot k P a$ $500*kPa$ . What is the new volume?

1 Answer

Explanation:

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A 2500⋅m32500*m^3 volume of gas under 200⋅kPa200*kPa pressure is compressed to 500⋅kPa500*kPa. What is the new volume?

1 Answer

Explanation:

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Impact of this question

A $2500 \cdot m^{3}$ $2500m^3$ volume of gas under $200 \cdot k P a$ $200kPa$ pressure is compressed to $500 \cdot k P a$ $500*kPa$ . What is the new volume?