What is the volume of "0.220 mols"0.220 mols of carbon monoxide gas found at STP?

1 Answer
Jun 3, 2016

If we assume that carbon monoxide ("CO"CO) is an ideal gas, then we can use the ideal gas law:

\mathbf(PV = nRT)PV=nRT

where:

  • PP is the pressure of the gas. We can use "bars"bars as our units.
  • VV is the volume of the gas in "L"L.
  • nn is the \mathbf("mol")mols of gas.
  • RR is the universal gas constant, "0.083145 L"cdot"bar/mol"cdot"K"0.083145 Lbar/molK.
  • TT is the temperature of the gas in "K"K.

At STP, T = 0^@ "C" = "273.15 K"T=0C=273.15 K, and P = "1 bar"P=1 bar. So, to get the volume, just solve for VV.

color(blue)(V_"CO") = (nRT)/PVCO=nRTP

= ((0.220 cancel("mol CO"))("0.083145 L"cdotcancel("bar")"/"cancel("mol")cdotcancel("K"))(273.15 cancel("K")))/(1 cancel"bar")

= color(blue)("5.00 L") to 3 sig figs.