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Question #9e62c

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May 15, 2016

For acetic acid, $H_{3} C - C (= O) O H$ $H_3C-C(=O)OH$ ?

Explanation:

$H_{3} C - C (= O) O H (a q) + H_{2} O ⇌ H_{3} C - C (= O) O^{-} + H_{3} O^{+}$ $H_3C-C(=O)OH(aq) + H_2O rightleftharpoons H_3C-C(=O)O^(-) + H_3O^+$

$K_{a} = \frac{[H_{3} O^{+}] [H_{3} C - C (= O) O^{-}]}{[H_{3} C - C (= O) O H (a q)]}$ $K_a = ([H_3O^+][H_3C-C(=O)O^-])/([H_3C-C(=O)OH(aq)])$

$K_{a} = 10^{- 4.76}$ $K_a = 10^(-4.76)$

May 15, 2016

Acetic acid has one ionization to the hydrogen ion and the acetate ion:
$H_3CCOOH ↔ H_3CCOO^-$ + $H^+$

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