Question #12933
1 Answer
Explanation:
You're dealing with a neutralization reaction in which nitric acid,
The balanced chemical equation that describes this reaction looks like this
"HNO"_ (3(aq)) + "LiOH"_ ((aq)) -> "LiNO"_ (3(aq)) + "H"_ 2"O"_((l))HNO3(aq)+LiOH(aq)→LiNO3(aq)+H2O(l)
Nitric acid is a strong acid, which means that it ionizes completely in aqueous solution to form hydronium cations,
"HNO"_ (3(aq)) + "H"_ 2"O"_ ((l)) -> "H"_ 3"O"_ ((aq))^(+) + "NO"_(3(aq))^(-)HNO3(aq)+H2O(l)→H3O+(aq)+NO−3(aq)
Lithium hydroxide is a strong base, so it too will ionize completely in aqueous solution to form lithium cations,
"LiOH"_ ((aq)) ->."Li"_ ((aq))^(+) + "OH"_((aq))^(-)LiOH(aq)→.Li+(aq)+OH−(aq)
The complete ionic equation for this reaction will look like this
"H"_ 3"O"_ ((aq))^(+) + "NO"_ (3(aq))^(-) + "Li"_ ((aq))^(+) + "OH"_ ((aq))^(-) -> "Li"_ ((aq))^(+) + "NO"_ (3(aq))^(-) + 2"H"_ 2"O"_((l))H3O+(aq)+NO−3(aq)+Li+(aq)+OH−(aq)→Li+(aq)+NO−3(aq)+2H2O(l)
The net ionic equation, which doesn't include spectator ions, will look like this
"H"_ 3"O"_ ((aq))^(+) + color(red)(cancel(color(black)("NO"_ (3(aq))^(-)))) + color(red)(cancel(color(black)("Li"_ ((aq))^(+)))) + "OH"_ ((aq))^(-) -> color(red)(cancel(color(black)("Li"_ ((aq))^(+)))) + color(red)(cancel(color(black)("NO"_ (3(aq))^(-)))) + 2"H"_ 2"O"_((l))
This is equivalent to
"H"_ 3"O"_ ((aq))^(+) + "OH"_ ((aq))^(-) -> 2"H"_ 2"O"_((l))
This tells you that the hydronium cations coming from the acid and the hydroxide anions coming from the base neutralize each other to form water.
