How many moles "Ag"_2"O" are needed to produce "4.24 mol O"_2"?

"2Ag"_2"O"rarr"4Ag + O"_2"

1 Answer
Meave60
May 21, 2016

"8.50 mol Ag"_2"O" are needed to produce "4.25 mol O"_2".

Explanation:

Balanced Equation

"2Ag"_2"O"rarr"4Ag"+"O"_2"

Multiply the given moles of "O"_2" times the mole ratio between "Ag"_2"O" and "O"_2" from the balanced equation, with "Ag"_2"O" as the numerator.

4.25cancel"mol O"_2xx(2"mol Ag"_2"O")/(1cancel"mol O"_2)="8.50 mol Ag"_2"O"

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