Find ${sin}^{- 1} \sqrt{\frac{3}{2}}$ $sin^(-1)sqrt(3/2)$ ?

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Answer 1 · 2017-02-14T06:48:46

${sin}^{- 1} \sqrt{\frac{3}{2}}$ $sin^(-1)sqrt(3/2)$ does not exist.

For any $x$ $x$ , we have $- 1 \leq sin x \leq 1$ $-1 <= sinx <= 1$ or $| sin x | \leq 1$ $|sinx|<=1$

but here assuming ${sin}^{- 1} \sqrt{\frac{3}{2}} = θ$ $sin^(-1)sqrt(3/2)=theta$

we will have $sin θ = \sqrt{\frac{3}{2}} = 1.2247$ $sintheta=sqrt(3/2)=1.2247$

but this is just not possible.

Hence ${sin}^{- 1} \sqrt{\frac{3}{2}}$ $sin^(-1)sqrt(3/2)$ does not exist.

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