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Question #e8e9c

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Answer 1 · 2016-06-04T12:29:25

$1.07 \times 10^{-3} m o l$ $1.07xx10^"-3"mol$

Explanation:

The temperature and pressure of the gas is not given in the question. It is assumed that it is at STP.

Accoding to the balanced equation 1 mole of $C O_{2}$ $CO_2$ is produced from 1 mole of $C a C O_{3}$ $CaCO_3$

At STP 1mole $C O_{2}$ $CO_2$ occupies 22400cc.

At STP 24 cc $C O_{2}$ $CO_2$ will be produced from $\frac{24}{22400} m o l = 1.07 \times 10^{-3} m o l C a C O_{3}$ $24/22400mol=1.07xx10^"-3"molCaCO_3$

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