Question #3a0ab

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Question #3a0ab

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Answer 1 · 2016-08-31T17:54:55

$0.01 m$ $0.01m$

Explanation:

We know for sonic and ultra sonic waves the velocity $v$ $v$ is related to frequency $n$ $n$ and wavelength $λ$ $lambda$ by the following expression

$v = n λ$ $v=nlambda$

Inserting given values we get
$1500 = 0.15 \times 10^{6} λ$ $1500=0.15xx10^6lambda$
$λ = \frac{1500}{0.15 \times 10^{6}}$ $lambda=1500/(0.15xx10^6)$
$λ = 0.01 m$ $lambda=0.01m$

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Question #3a0ab

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