How are oxidation numbers assigned?

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How are oxidation numbers assigned?

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Answer 1 · 2016-06-25T07:03:37

All these compounds?

Explanation:

The oxidation number of oxygen in OXIDES is generally $- I I$ $-II$ . The oxidation number of a metal is generally its Group Number; i.e. $barium$ $"barium"$ as a $Group II$ $"Group II"$ metal generally has a $I I +$ $II+$ oxidation state in its compounds. An element has an oxidation number of $0$ $0$ ; i.e. it is zerovalent; $O_{2}$ $O_2$ gas is zerovalent because it has not reacted with (oxidized) anything. The sum of the oxidation numbers is equal to the charge on the ion; viz. $C O_{3}^{2 -}$ $CO_3^(2-)$ , if oxygen is $- I I$ $-II$ (and it is!), then $C$ $C$ has a $I V +$ $IV+$ oxidation state.

I am unwilling to assign the other oxidation numbers until you make an attempt.

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How are oxidation numbers assigned?

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