Question #1de6c

1 Answer
Jul 26, 2017

No, it can't be.

Explanation:

6x^2+6x^3=6x^2(1+x)

6x^2=6x^2+0x+0->ax^2+bx+c :
By doing this, we are assuming that f(x) = y = 6x^2 =0.

x=(-b+-sqrt(b^2-4ac))/(2a)->=0

(In this case:)
x = (-0+-sqrt(0^2-4*1*0))/(2) = = (0+- 0)/2 = 0

So far, so good.

6*0^2*(1+0) = 0 * (1+0) = 0 * (1) = 0.
This is the real answer considering that what we had assumed (f(x) = 0) was true.
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A real and good simplification would just be 6x^2(1+x), because it does not envolve any other factors (such as y) in the simplification.