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Answer 1 · 2016-07-10T08:06:34

#sin^2x/(1+cosx)=1-cosx=2sin^2(x/2).#

We know that, #sin^2x=1-cos^2x=(1+cosx)(1-cosx)#

#:. sin^2x/(1+cosx)=1-cosx.#

If we use, the formula, #: 1-cos2theta=2sin^2(theta/2)#, the above Exp. can still be expressed as #2sin^2(x/2).#

Altogether, #sin^2x/(1+cosx)=1-cosx=2sin^2(x/2).#

Answer 2 · 2016-07-10T08:06:37

#sin^2x/(1+cosx)=1-cosx=2sin^2(x/2).#

We know that, #sin^2x=1-cos^2x=(1+cosx)(1-cosx)#

#:. sin^2x/(1+cosx)=1-cosx.#

If we use, the formula, #: 1-cos2theta=2sin^2(theta/2)#, the above Exp. can still be expressed as #2sin^2(x/2).#

Altogether, #sin^2x/(1+cosx)=1-cosx=2sin^2(x/2).#