Question #2f990

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Question #2f990

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Answer 1 · 2016-07-22T17:54:20

Kinetic energy increases by 21%

Explanation:

$\to p = m \to v$ $vec(p) = mvec(v)$

Assuming this increase occurs in the same direction we will just work with magnitudes. I've also assumed this is classical mechanics and that the mass remains constant.

$p = m v$ $p = mv$

The object starts with $p_{1} = m v_{1}$ $p_1 = mv_1$ and ends with $p_{2} = m v_{2} = 1.1 p_{1}$ $p_2 = mv_2 = 1.1p_1$ .

$(p_2)/(p_1) = (cancel(m)v_2)/(cancel(m)v_1) = (v_2)/(v_1)$

$therefore v_2 = v_1(p_2)/(p_1) = 1.1v_1$

Kinetic energy given by

$KE = 1/2mv^2$

$(KE_2)/(KE_1) = (cancel(1/2m)(v_2)^2)/(cancel(1/2m)(v_1)^2)$

$KE_2 = (1.1v_1)^2/(v_1)^2KE_1$

$KE_2 = 1.21KE_1$

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Question #2f990

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