Question

Question #3365f

Answer 1

The required angle is `59.04^0(2dp)`

Explanation:

Let "p" be height where ladder rests on wall and "b" be the base distance of the ladder from wall at ground, then `tan theta=p/b=50/30=5/3:.theta=tan^-1(5/3)=59.04^0(2dp)`[Ans]