Factorize #25x^2+60x+36#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Shwetank Mauria Jul 26, 2016 #25x^2+60x+36=(5x+6)^2# Explanation: In #25x^2+60x+36#, the first and third term are complete square as #25x^2=(5x)^2# and #36=6^2# and middle term is double the product of #5x# and #3# i.e. #2xx5x xx6=60x# Hence using the identity #(a+b)^2=a^2+2ab+b^2# #25x^2+60x+36# = #(5x)^2+2xx5x xx6x+6^2# = #(5x+6)^2# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 6457 views around the world You can reuse this answer Creative Commons License