Question

Question #d30b9

Answer 1

Most versions on an epsilon-delta definition require `delta > 0`.

Explanation:

Perhaps the definition you're working with is something like:

`lim_(xrarra^-)f(x) = -oo` if and only if, for every `B`, there is a `delta > 0` such that for every `x`, if `a- delta < x < a`, then `f(x) < B`.

This allows for the possibility that `B` is a positive number, in which case `-1/B` would be negative..

Without knowing exactly what definition you're working with, I can only suggest that that's the problem.