Question #5b44c

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Question #5b44c

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Answer 1 · 2016-08-07T04:19:26

$x = 0 and y \leq 0$ $x = 0 and y<=0$

Explanation:

$θ = - \frac{9}{2} π$ $theta = -9/2pi$ separates Q3 and Q4. Sine is negative in Q3 and

Q4. and so,

$sin (- \frac{9}{2} π) = - 1, and cos (- \frac{9}{2} π) = 0$ $sin (-9/2pi)=-1, and cos (-9/2pi)=0$

Conversion formula is

$(x, y) = r (cos θ, sin θ) = r (cos (- \frac{9}{2} π), sin (- \frac{9}{2} π) = r (0, - 1)$ $(x, y) = r(cos theta, sin theta) = r(cos(-9/2pi), sin (-9/2pi) = r(0, -1)$ .

So, $x = 0 and y = - r \leq 0$ $x = 0 and y = -r <= 0$ .

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Question #5b44c

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