Question #5b44c Trigonometry The Polar System Converting Between Systems 1 Answer A. S. Adikesavan Aug 7, 2016 #x = 0 and y<=0# Explanation: #theta = -9/2pi# separates Q3 and Q4. Sine is negative in Q3 and Q4. and so, #sin (-9/2pi)=-1, and cos (-9/2pi)=0# Conversion formula is #(x, y) = r(cos theta, sin theta) = r(cos(-9/2pi), sin (-9/2pi) = r(0, -1)#. So, #x = 0 and y = -r <= 0#. Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1290 views around the world You can reuse this answer Creative Commons License