Question

Question #ac5ff

Answer 1

`LHS=sinx-2sin(x/2 - 15°)cos(x/2 +15°)`

`=sinx-(sin(x/2 - 15°+x/2 +15°)-sin(x/2 +15°-(x/2 - 15))`

`=sinx-(sinx-sin30°)`

`=sinx-sinx+sin30°`

`=sin30^@=1/2=RHS`

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