Question #290f5

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Answer 1 · 2016-09-06T20:01:10

$P(A | B)=5/8=0.625, and, P(AnnB')=0.175$

We know that, $P(AuuB)=P(A)+P(B)-P(AnnB)..........(1)$ .

But, we are given that, $P(AuuB)=3P(AnnB)$ .

$:." By "(1), 3P(AnnB)=P(A)+P(B)-P(AnnB), i.e., 4P(AnnB)=P(A)+P(B)$

Here, $P(A)=0.3, P(B)=0.2", so that, "P(AnnB)=0.5/4=1/8...(star)$

Now, $P(A | B)=(P(AnnB))/(P(B))=(1/8)/(1/5)=5/8=0.625$

$P(AnnB')=P(A-AnnB)=P(A)-P(AnnB)=0.3-0.125=0.175$ .

Enjoy Maths.!