Question #d943b

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Question #d943b

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Answer 1 · 2016-08-09T15:59:39

$p H = 10$ $pH=10$

Explanation:

In aqueous solution $p H + p O H = 14$ $pH+pOH=14$ ; I am not going thru another derivation. It is fairly straighforward.

We are given $[M^{+}] [H O^{-}] = 10^{- 8}$ $[M^+][HO^-]=10^-8$ ; in a saturated solution, thus $[M^{+}]$ $[M^+]$ $=$ $=$ $[H O^{-}]$ $[HO^-]$ $=$ $=$ $10^{- 4} \cdot m o l \cdot L^{- 1}$ $10^-4*mol*L^-1$ .

$p O H = 4$ $pOH=4$ , and from above $p H = 10$ $pH=10$ as required.

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Question #d943b

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