Why is $B F_{3}$ $BF_3$ considered to be a non-polar molecule, any yet $B - F$ $B-F$ bonds are polar?

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Why is $B F_{3}$ $BF_3$ considered to be a non-polar molecule, any yet $B - F$ $B-F$ bonds are polar?

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Answer 1 · 2016-08-11T15:07:26

Molecular polarity results from the $vector sum$ $"vector sum"$ of the individual bond dipoles.

Explanation:

We know (i) the the $B - F$ $B-F$ bond is polar; and (ii) that the $∠ F - B - F$ $/_F-B-F$ bond angles are $120^{\circ}$ $120""^@$ . When the individual bond dipoles are summed in a vector fashion, the resultant is necessarily $0$ $0$ . Thus boron trifluoride is non-polar. Capisce?

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Why is $B F_{3}$ $BF_3$ considered to be a non-polar molecule, any yet $B - F$ $B-F$ bonds are polar?

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Why is BF3BF_3 considered to be a non-polar molecule, any yet B−FB-F bonds are polar?

1 Answer

Explanation:

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Why is $B F_{3}$ $BF_3$ considered to be a non-polar molecule, any yet $B - F$ $B-F$ bonds are polar?