Question #40068

1 Answer
Aug 18, 2016

Bouyant force will decrease as it makes the volume of the object

Explanation:

As Archimedes' principle explains:

The apparent weight of an object, W_"apparent", in a fluid equals to its weight, W, minus the weight of the fluid which occupes its volume, B

W_"apparent" = W - B

where B is buoyant force.

If you put a body on a fluid, it will occupe some volume of fluid. If this fluid has a density rho, and the volume of the object is V, the mass of fluid which will be occupied is:

m_"fluid" = rho V

And the weight of this mass is right the buoyant force:

B = m_"fluid" cdot g = rho V g

As you see, buoyant force does not depend on the mass of the submerged body, but its volume. If you decrease its size, B will reduce.