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$a_{n} = sin (π \frac{n}{6}) + cos (π n)$ $a_n = sin(pi n/6)+cos(pi n)$ ?

1 Answer

Oct 6, 2016

See below.

Explanation:

$a_{n} = sin (π \frac{n}{6}) + cos (π n)$ $a_n = sin(pi n/6)+cos(pi n)$

This is a periodic sequence in which

$a_{n} = a_{n + 12}$ $a_n = a_(n+12)$ with minimum and maximum values such that

$- 2 \leq a_{n} \leq 1 + \frac{\sqrt{3}}{2}$ $-2 le a_n le 1+sqrt(3)/2$

Attached a sequence plot

enter image source here

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