Question #04a12

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Answer 1 · 2016-08-28T05:53:05

Assuming the situation is that where a piece of ice is dropped in a glass of water at room temperature which is much greater than $4^@C$

To explain let us consider

$M_i->"Mass of the piece of ice floated"$

$d_w="Density of water"$

Volume of water obtained on melting ice $V_w=M_i/d_w$

As the ice is floating then by the condition of floatation,

The mass of water displced by floating ice is same as the mass of ice $M_i$
So the volume of this displaced water $=V_d=M_i/d_w$

Since $V_w=V_d$ ,we can easily say the water level will remain at the same position as before the melting of floated ice in water.