Question #7f247

1 Answer
Aug 28, 2016

WARNING! Long answer. (a) The C-terminus is glycine. (b) There are 4 charged groups at pH 7. (c) At pH 1 the net charge is +2. (d) The sequence using one-letter symbols is "E-M-R-T-G".

Explanation:

(a) C-terminus

In a peptide, the amino acids are written from left to right with the "NH"_2 group on the left and the "C=O" group on the right.

The left hand amino acid is called the N-terminus, and the right hand amino acid is called the C-terminus.

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Thus, in "Glu-Met-Arg-Thr-Gly", the C-terminus is Gly (glycine).

(b) Charged groups at pH 7

There are three points to remember:

  • If "pH = p"K_a, the neutral and ionic forms are present in equal amounts.
  • If "pH < p"K_a (i.e. more acidic), the protonated form will predominate.
  • If "pH > p"K_a (i.e. more basic), the non-protonated form will predominate.

Both Met (methionine) and Thr (threonine) have neutral R-groups, and they are neither N-terminal or C-terminal amino acids, so we can ignore them in our calculations.

Glu (glutamic acid) has both a basic N-terminus and an acidic R-group.

The corresponding "p"K_"a" values are

pH 7

The red line marks the pH 7 division mark.

For Gly, "pH > pK"_"a", so the non-protonated form ("COO"^"-") will predominate.

For Arg, "pH < pK"_"a", so the protonated form ("NH"_3^+) will predominate.

For the R-group of Glu, "pH > pK"_"a", so the non-protonated form ("COO"^"-") will predominate.

However, for the N-terminal group of Glu, "pH < pK"_"a", so the protonated form ("NH"_3^+) will predominate.

Thus, there are four ionized groups at pH 7.

(c) Net charge at pH 1

At pH 1, all groups have "pH < pK"_"a", so the protonated forms will predominate..

pH 1

For the C-terminal group of Gly and the R-group of Glu, the protonated forms are "COOH".

For the N-terminal group of Glu and the R-group of Arg, the protonated forms are "NH"_3^+.

Thus, at pH 1 the net charge is +2.

(d) Sequence using one-letter symbols

The one-letter symbols for the amino acids are

"Arg = R"
"Glu = E"
"Gly = G"
"Met = M"
"Thr = T"

"Glu-Met-Arg-Thr-Gly = E-M-R-T-G".