Two numbers add to #13# and multiply to #42#. What are the two numbers?

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Answer 1 · 2016-09-01T02:30:46

The numbers are #6# and #7#.

Let the first number be #x# and the second be #y#.

#x + y = 13#

#xy = 42#

#y = 13 - x#

#x(13 - x) = 42#

#13x - x^2 = 42#

#0 = x^2 - 13x + 42#

#0 = (x - 7)(x - 6)#

#x = 7 and 6#

#:.# The numbers are #7# and #6#.

Hopefully this helps!