How do you find the missing yy values for a line with a slope of -1010 which goes through (2, 8)(2,8) and (3, s)(3,s)?

1 Answer
Jun 11, 2017

See a solution process below:

Explanation:

The slope can be found by using the formula: m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))m=y2y1x2x1

Where mm is the slope and (color(blue)(x_1, y_1)x1,y1) and (color(red)(x_2, y_2)x2,y2) are the two points on the line.

Substituting the slope and values from the points in the problem gives:

-10 = (color(red)(8) - color(blue)(s))/(color(red)(2) - color(blue)(3))10=8s23

We can now solve for ss:

-10 = (color(red)(8) - color(blue)(s))/-110=8s1

-10 = -(color(red)(8) - color(blue)(s))/110=8s1

-10 = -(color(red)(8) - color(blue)(s))10=(8s)

-10 = -color(red)(8) + color(blue)(s)10=8+s

8 - 10 = 8 - color(red)(8) + color(blue)(s)810=88+s

-2 = 0 + color(blue)(s)2=0+s

-2 = color(blue)(s)2=s

color(blue)(s) = -2s=2