Question #3457f

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Question #3457f

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Answer 1 · 2016-09-03T18:33:59

Slope is -2
y-intercept at y=2 $\to (x, y) = (0, 2)$ $->(x,y)=(0,2)$

Explanation:

You could manipulate this into the form of $y = m x + c$ $y=mx+c$ but you only need to do this in part but in trying to cut corners you could make a mistake. So lets convert it!

divide both sides by 4 giving

$2 x + y = 2$ $2x+y=2$

subtract $2 x$ $2x$ from both sides

$y = - 2 x + 2$ $y=-2x+2$

$The slope (gradient) is m in y = m x + c \Rightarrow m = - 2$ $color(blue)("The slope (gradient) is m in "y=mx+c" " =>" " m=-2)$

The y-intercept is when $x = 0$ $x=0$

Thus we have $y = - 2 x + 2 \to y = - 2 (0) + 2$ $color(brown)(y=-2x+2)color(green)(" "->" "y=-2(0)+2)$

$y_{intercept} = 2$ $color(blue)(y_("intercept")=2)$

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Question #3457f

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