How many atoms exist in a #23*g# mass of sodium metal?

Question

7480 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-05T17:22:59

Yes (and sort of no)

1 mole of Na = #6.022140857(74)×10^"23"# atoms .

Note the use of the word atoms .

1 mole of #Na^+# would be #6.022140857(74)×10^"23"# ions .

I may seem to be overly pedantic in this, but science is all about accuracy.

The number - #6.022140857(74)×10^"23"# - is called the Avogadro constant and you can read more about it on Wikipedia.

Answer 2 · 2016-09-05T17:23:00

#1*"mole"# of sodium metal #-=# #6.022xx10^23# atoms NOT ions.

#1*"mole"# of #Na^+# #-=# #6.022xx10^23# ions.

Of course we can make ions from atoms and atoms from ions and vice versa.

#Na(g) rarr Na^(+)(g) + e^(-)(g)#.

Given #22.99*g# of metal, there are molar quantities of atoms, ions, and electrons. The given stoichiometry demands this.