How is hydrogen formed from zinc and methane under basic conditions?

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How is hydrogen formed from zinc and methane under basic conditions?

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Answer 1 · 2016-10-09T18:02:05

You form the zincate ion from zinc and hydroxide, and methane and water give the so-called steam reforming reaction.

Explanation:

Zinc is quite an active metal, and will be oxidized by EITHER $H_{3} O^{+}$ $H_3O^+$ or $H O^{-}$ $HO^-$ . Dihydrogen is the reduction product.

$Z n (s) + 2 N a O H (a q) + 2 H_{2} O (l) \to 2 N a^{+} + Z n {(O H)}_{4}^{2 -} + H_{2} (g) ↑ ⏐ ⏐$ $Zn(s) + 2NaOH(aq) +2H_2O(l) rarr 2Na^(+) + Zn(OH)_4^(2-) +H_2(g)uarr$

Methane gas and steam (+ energy) will give dihydrogen gas and carbon dioxide:

$C H_{4} (g) + 2 H_{2} O (l) + energy \to C O_{2} (g) + 4 H_{2} (g)$ $CH_4(g) + 2 H_2O(l) + "energy "rarr CO_2(g) + 4H_2(g)$

Are these reactions balanced? They should be!

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How is hydrogen formed from zinc and methane under basic conditions?

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