Question

Question #bc809

Answer 1

`3f(2x)=3(8x^2-6x+1)=24x^2-18x+3`.

Explanation:

Given: `f(x) = 2x^2-3x+1`, to find `3f(2x)", or, in fact, "f(2x)`,

what we have to do is : simply replace `x`, in the formula given for

`f(x)`, by `2x`, as shown below :

`f(x) = 2x^2-3x+1 rArr f(2x)=2(2x)^2-3(2x)+1`

`=2(4x^2)-6x+1=8x^2-6x+1`.

`" Therefore, "3f(2x)=3(8x^2-6x+1)=24x^2-18x+3`.