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Question #bc809

1 Answer

Sep 12, 2016

$3 f (2 x) = 3 (8 x^{2} - 6 x + 1) = 24 x^{2} - 18 x + 3$ $3f(2x)=3(8x^2-6x+1)=24x^2-18x+3$ .

Explanation:

Given: $f (x) = 2 x^{2} - 3 x + 1$ $f(x) = 2x^2-3x+1$ , to find $3 f (2 x), or, in fact, f (2 x)$ $3f(2x)", or, in fact, "f(2x)$ ,

what we have to do is : simply replace $x$ $x$ , in the formula given for

$f (x)$ $f(x)$ , by $2 x$ $2x$ , as shown below :

$f (x) = 2 x^{2} - 3 x + 1 \Rightarrow f (2 x) = 2 {(2 x)}^{2} - 3 (2 x) + 1$ $f(x) = 2x^2-3x+1 rArr f(2x)=2(2x)^2-3(2x)+1$

$= 2 (4 x^{2}) - 6 x + 1 = 8 x^{2} - 6 x + 1$ $=2(4x^2)-6x+1=8x^2-6x+1$ .

$Therefore, 3 f (2 x) = 3 (8 x^{2} - 6 x + 1) = 24 x^{2} - 18 x + 3$ $" Therefore, "3f(2x)=3(8x^2-6x+1)=24x^2-18x+3$ .

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