Question

Question #03617

Answer 1

`((a = -2, b = -7),(a = 0, b = 5))`

Explanation:

Given

`p(x) = (1 + x)^5 (1 + a x)^6 = sum_(k=0)^11 c_kx^k`

we know that

`c_k = (1/(k!)(d^kp)/(dx^k))_(x=0)`

so

`c_1 = 5+6a =b`
`c_2=10 + 30 a + 15 a^2 = 10`

Solving for `a,b` we have two outcomes

`((a = -2, b = -7),(a = 0, b = 5))`