Question #bef4d

1 Answer
Sep 17, 2016

x=4"; "y=6x=4; y=6

Explanation:

Given:
" "x=y-2 x=y2..................Equation(1)
" "3x-y=6 3xy=6...............Equation(2)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(green)("Determine the value of "y)Determine the value of y

color(purple)("Method shown in great detail")Method shown in great detail

Substitute for xx in equation(2) using equation(1)

color(brown)(3x-y=6)color(blue)(" "->" "3(y-2)-y=63xy=6 3(y2)y=6

3y-6-y=63y6y=6

2y-6=62y6=6

Add 6 to both sides

2y-6+6=6+62y6+6=6+6

2y+0=122y+0=12

Divide both sides by 2

2/2xx y=12/222×y=122

color(green)(y=6)y=6
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
color(green)("Determine the value of "x)Determine the value of x

Given that y=6y=6 equation(1) becomes:

x=6-2" "........................Equation(1_a)

color(green)(x=4)