Question #b6602

1 Answer
Ernest Z.
Sep 20, 2016

Here's what I get.

Explanation:

a) #"CH"_3"CH"_2"CH"_2"-OH" + "SOCl"_2 → "CH"_3"CH"_2"CH"_2"-Cl" + "SO"_2 + "HCl"#

b) #"CH"_3"CH"_2"CH"_2"-OH" + "POCl"_3 + "Py" → "CH"_3"CH=CH"_2 + "PyH"^+ stackrel(-)("O")"POCl"_2#

c) #"CH"_3"CH"_2"CH"_2"CH"_2"-OH" + "HCl" stackrelcolor(blue)(Δcolor(white)(m))(→) "CH"_3"CH"_2"CH"_2"CH"_2"-Cl" + "H"_2"O"#

Related questions
See all questions in E1 and E2 Reactions
Impact of this question
1698 views around the world
You can reuse this answer
Creative Commons License