Question #0a300

1 Answer
Sep 20, 2016

lim_(x to 0^-) sqrt (3 + arctan(1/x)) = sqrt (3 - pi/2)

lim_(x to 0^+) sqrt (3 + arctan(1/x)) = sqrt (3 + pi/2)

Explanation:

lim_(x to 0) sqrt (3 + arctan(1/x))

now we can plot this to see where this limit is going....

Desmos

....so we can see that

lim_(x to 0) sqrt (3 + arctan(1/x)) \ \ \ is two sided

We know that:

lim_(x to 0^-) arctan(1/x) = - pi/2

lim_(x to 0^) arctan(1/x) = pi/2

So
lim_(x to 0^-) sqrt (3 + arctan(1/x)) = sqrt (3 - pi/2)

lim_(x to 0^+) sqrt (3 + arctan(1/x)) = sqrt (3 + pi/2)