Question #6a649

1 Answer
Sep 22, 2016

See below.

Explanation:

This is an integral that cannot be obtained in closed form. In those cases you can try to integrate the series representation to obtain an answer.

Taking as an example

int x^x dxxxdx which is also an integral not obtainable in closed form,
developping in series

(1+x)^(1+x) = sum_(k=0)^oo((Pi_(j=1)^k(x-j+2))/(k!))x^k or

(1+x)^(1+x) = 1 + x (1 + x) + 1/2 x^3 (1 + x) + 1/6 (x-1) x^4 (1 + x)+cdots

Convergent for -1le x le 1

Now, with 0 le x le 2 you can approximate the integral obtaining

intx^xdx approx sum_(k=0)^nint((Pi_(j=1)^k(x-j+1))/(k!))(x-1)^kdx